How do you solve #2x+3(x-2)>=x+2#?

1 Answer
Meave60
Mar 30, 2017

#x>=2#

Explanation:

Solve:

#2x+3(x-2)>=x+2#

Expand.

#2x+3x-6>=x+2#

Subtract #x# from both sides.

#2x+3x-x-6>=2#

Add #6# to both sides.

#2x+3x-x-6+6>=x-x+2+6#

Simplify.

#2x+3x-x-color(red)cancel(color(black)(6))+color(red)cancel(color(black)(6))>=color(red)cancel(color(black)(x))-color(red)cancel(color(black)(x))+2+6#

#4x>=8#

Divide both sides by #4#.

#(color(red)cancel(color(black)(4))x)/color(red)cancel(color(black)(4))>=color(red)cancel(color(black)(8))^color(blue)2/color(red)cancel(color(black)(4))^color(blue)1#

#x>=2#

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