Question #836cd
1 Answer
Mar 24, 2017
Explanation:
differentiate using the
#color(blue)"product rule"#
#"Given " y=g(x)h(x)" then"#
#color(red)(bar(ul(|color(white)(2/2)color(black)(dy/dx=g(x)h'(x)+h(x)g'(x))color(white)(2/2)|)))#
#color(orange)"Reminder : " d/dx(sin(f(x))=cos(f(x)).f'(x)# The same applies to
#d/dx(cos(f(x)))=-sin(f(x)).f'(x)#
#"here " g(x)=sin(mx)rArrg'(x)=mcos(mx)#
#"and " h(x)=cos(nx)rArrh'(x)=-nsin(nx)#
#rArrdy/dx=sin(mx)(-nsin(nx)+cos(nx)(mcos(mx)#
#color(white)(rArrdy/dx)=mcos(mx)cos(nx)-nsin(mx)sin(nx)#
