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Question #209a9

1 Answer

Mar 24, 2017

Use the product rule :

#dy/dx= (f(x)g(x))'=f'(x)g(x)+f(x)g'(x)#

Explanation:

Use the product rule :

#dy/dx= (f(x)g(x))'=f'(x)g(x)+f(x)g'(x)#

let #f(x) = e^(3x) and g(x) = sin(4x)#, then it follows that #f'(x) = 3e^(3x) and g'(x)=4cos(4x)#

#dy/dx=(3e^(3x))(sin(4x))+(e^(3x))(4cos(4x))#

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