Question #400e8

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Answer 1 · 2017-03-12T09:08:34

#(dy)/(dx)=tanx+xsec^2x#

this will require the product rule for differentiation

#y=uv=>(dy)/(dx)=u'v+uv'#

where both #" "u" " & " "v" are both functions of" #x#

#y=xtanx#

#u=x=>u'=1#

#v=tanx=>v'=sec^2x#

#(dy)/(dx)=tanx+xsec^2x#