Question #72bda
1 Answer
Mar 2, 2017
Your answer is correct, it just has a different
Explanation:
So
= log(3/2) + log abs( (2t+1)/(3t+2)) +C_1
= log abs( (2t+1)/(3t+2)) +C_2
Your answer is correct, it just has a different
So
= log(3/2) + log abs( (2t+1)/(3t+2)) +C_1
= log abs( (2t+1)/(3t+2)) +C_2