Question #7bb02

Question

Question #7bb02

1 Answer

Impact of this question

1469 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-02-17T13:59:58

Given expression is
#y= 3e^x+ 4/(root(3)(x)#
#=>y= 3e^x+ 4(x)^(-1/3)#
Differentiating
#y'= d/dx(3e^x+ 4(x)^(-1/3))#
#=>y'= d/dx(3e^x)+ d/dx(4(x)^(-1/3))#
#=>y'= 3e^x+ 4xx(-1/3)(x)^(-1/3-1)#
#=>y'= 3e^x- 4/3(x)^(-4/3)#
#=>y'= 3e^x- 4/(3(x)^(4/3))#
#=>y'= 3e^x- 4/(3root(3)(x^4)#

Science

Math

Humanities

... and beyond

Question #7bb02

1 Answer

Related questions

Impact of this question