Question #7bb02

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Question #7bb02

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Answer 1 · 2017-02-17T13:59:58

Given expression is
#y= 3e^x+ 4/(root(3)(x)#
#=>y= 3e^x+ 4(x)^(-1/3)#
Differentiating
#y'= d/dx(3e^x+ 4(x)^(-1/3))#
#=>y'= d/dx(3e^x)+ d/dx(4(x)^(-1/3))#
#=>y'= 3e^x+ 4xx(-1/3)(x)^(-1/3-1)#
#=>y'= 3e^x- 4/3(x)^(-4/3)#
#=>y'= 3e^x- 4/(3(x)^(4/3))#
#=>y'= 3e^x- 4/(3root(3)(x^4)#

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Question #7bb02

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