Question #b7d22 Calculus Basic Differentiation Rules Chain Rule 1 Answer A08 Feb 13, 2017 Given #y=sin^3 5x# Using chain rule to calculate derivative #y'=d/dx(sin^3 5x)# #=>y'=(3sin^2 5x)(cos5x)(5)# #=>y'=15sin^2 5xcos5x# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1736 views around the world You can reuse this answer Creative Commons License