Question #f17c9

Question

1628 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-01-31T13:03:37

We know the expression for dispersive power #omega# as follows

#omega=(mu_b-mu_r)/(mu_y-1#

where

#mu_b->"refractive index in respect of blue light"#

#mu_r->"refractive index in respect of red light"#

#mu_y->"refractive index in respect of yellow light"#

Given

#omega=0.031" "mu_b=1.665" "mu_r=1.645#

So inserting the values we have

#omega=(mu_b-mu_r)/(mu_y-1#

#=>0.031=(1.665-1.645)/(mu_y-1#

#=>mu_y-1=0.020/0.031#

#=>mu_y=20/31+1=51/31~~1.64516#