Question #f17c9

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Answer 1 · 2017-01-31T13:03:37

We know the expression for dispersive power $omega$ as follows

$omega=(mu_b-mu_r)/(mu_y-1$

where

$mu_b->"refractive index in respect of blue light"$

$mu_r->"refractive index in respect of red light"$

$mu_y->"refractive index in respect of yellow light"$

Given

$omega=0.031" "mu_b=1.665" "mu_r=1.645$

So inserting the values we have

$omega=(mu_b-mu_r)/(mu_y-1$

$=>0.031=(1.665-1.645)/(mu_y-1$

$=>mu_y-1=0.020/0.031$

$=>mu_y=20/31+1=51/31~~1.64516$