Question #e1818

Question

Question #e1818

1 Answer

Impact of this question

6662 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-10-02T13:45:28

Summing up the number of $sigma$ -bond formed by the desired atom (here N) and the number of lone pair on it we can easily know the hybridization of it.

$"If the sum is 2 "->"hybridization"-sp$

$"If the sum is 3 "->"hybridization"-sp^2$

$"If the sum is 4 "->"hybridization"-sp^3$

$"If the sum is 5 "->"hybridization"-sp^3d$

$"If the sum is 6 "->"hybridization"-sp^3d^2$

Inspecting the Lewis structure of $H-CequivN:$ we see that N-atom has one $sigma$ -bond and one lone pair so sum is 2.
Hence the hybridization is sp.

Science

Math

Humanities

... and beyond

Question #e1818

1 Answer

Related questions

Impact of this question