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How is #"cuprous ion"# oxidized by bleach to give #"cupric ion"#?

1 Answer

Sep 11, 2016

This is a redox reaction; cuprous ion is oxidized by bleach to cupric ion.

Explanation:

#ClO^(-) +2H^(+) + 2e^(-) rarr Cl^(-) + H_2O(l)#, #"reduction"#

#Cu^(+) rarr Cu^(2+) + 1e^(-)#, #"oxidation"#

#2Cu^(+) + ClO^(-) +2H^(+)rarr 2Cu^(2+) + Cl^(-) + H_2O(l)#.

Charge and mass are balanced, so this equation is reasonable.

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