Question #185fb

Step 1. Draw the bond-line structure of the molecule.

We see immediately that the longest continuous chain has 7 carbon atoms.

The correct name is 1-choro-3,5-dimethylheptane.

Step 2. Convert it to a wedge-dash structure at `"C-3"` and `"C-4"`.

Step 3. Identify the groups on `"C-3"` and `"C-4"`.

The main chain of hexane is the horizontal zig-zag line of carbon atoms.

`"C-1"` is on the right.

The groups on `"C-3"` are `"H"`, `"CH"_3` and `"CH"_2"CH"_2"Cl"`.

Those on `"C-4"` are `"H"`, `"H"`, and `"CH"("CH"_3)"CH"_2"CH"_3`.

Step 4. Draw a template for a Newman projection.

Step 5. Attach the groups to the carbons of your template.

View the molecule from the upper left.

The groups on `"C-4"` go on the front carbon atom. Put the `"CH"("CH"_3)"CH"_2"CH"_3`. group on the bottom. The two `"H"` atoms go on the other bonds.

The groups on `"C-3"` go on the back carbon. The bulky `"CH"_2"CH"_2"Cl"` group goes on the top. The `"CH"_3` group and the `"H"` atom go on the other bonds.

This is the most stable conformer, because it has the bulky 2-chloroethyl and sec-butyl groups anti to each other.