How do you rationalise the denominator in #3/sqrt3#?

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Answer 1 · 2016-09-01T21:59:49

#sqrt3#

Its is not good maths practice to leave a surd in the denominator, it's preferable in the numerator.

Note that: #sqrt(x^2) = x " and " x = sqrtx xx sqrtx #

#3/sqrt3 xx sqrt3/sqrt3#

=# (cancel3sqrt3)/cancel3#

=#sqrt3#

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An alternative method:

#3/sqrt3 = (sqrt3xxsqrt3)/sqrt3#

#(cancelsqrt3xxsqrt3)/cancelsqrt3#

=#sqrt3#