How do you rationalise the denominator in $3/sqrt3$ ?

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Answer 1 · 2016-09-01T21:59:49

$sqrt3$

Its is not good maths practice to leave a surd in the denominator, it's preferable in the numerator.

Note that: $sqrt(x^2) = x " and " x = sqrtx xx sqrtx$

$3/sqrt3 xx sqrt3/sqrt3$

= $(cancel3sqrt3)/cancel3$

= $sqrt3$

`
An alternative method:

$3/sqrt3 = (sqrt3xxsqrt3)/sqrt3$

$(cancelsqrt3xxsqrt3)/cancelsqrt3$

= $sqrt3$

How do you rationalise the denominator in 3/sqrt33/sqrt3?