Simplify $sqrt300-sqrt48$ ?

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Answer 1 · 2016-10-04T09:05:05

$sqrt300-sqrt48=6sqrt3$

$sqrt300$

= $sqrt(2xx2xx3xx5xx5)$

= $sqrt(ul(2xx2)xx3xxul(5xx5))$

= $2xx5xxsqrt3$

= $10sqrt3$

Similarly $sqrt48$

= $sqrt(2xx2xx2xx2xx3)$

= $sqrt(ul(2xx2)xxul(2xx2)xx3)$

= $2xx2xxsqrt3$

= $4sqrt3$

Hence $sqrt300-sqrt48$

= $10sqrt3-4sqrt3$

= $(10-4)sqrt3$

= $6sqrt3$

Simplify sqrt300-sqrt48sqrt300-sqrt48?