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Question #9a020

1 Answer

Jul 12, 2016

#p(-2) = 12#

Explanation:

I am assuming that #p(x) = x^3 + 7x^2 + 4x# and you want to find #p(-2)#.

If this is the case, then plug in #-2# for all variables #x#.

#p(x) = x^3+7x^2+4x#

#p(-2)= (-2)^3 + 7(-2)^2 + 4(-2)#

#p(-2) = -8 + 28 -8#

#p(-2) = 20 - 8#

#p(-2) = 12#

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