Question #d0666

1 Answer
P dilip_k
Jun 4, 2016

#-130kJmol^"-1"#

Explanation:

#DeltaH_"reaction"=H_"product"-H_"reactant"....(1)#

#DeltaE_"activation"=E_"TS"-H_"reactant"....(2)#

Energy released during bond formation

#DeltaH_"bond formation"=H_"product"-E_"TS"#

Subtracting (2) rom(1) We get

#DeltaH_"reaction"-DeltaE_"activation"=H_"product"- E_"TS"=DeltaH_"bond formation"#

Given

#DeltaH_"reaction"=53kJmol^"-1"#

#DeltaE_"activation"=183kJmol^"-1"#

#:.DeltaH_"bond formation"=(53-183)kJmol^"-1"=-130kJmol^"-1"#

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