Question #28fed
1 Answer
May 29, 2016
Explanation:
You wish to find:
int(1-2x)/(2x^2-2x+5)dx
Let
Multiply the numerator of the integrand by
=-1/2int(-2(1-2x))/(2x^2-2x+5)dx=-1/2int(4x-2)/(2x^2-2x+5)dx
Substitute in
=-1/2int(du)/u
Note that
=-1/2ln(2x^2-2x+5)+C
Note that the absolute value signs are not needed because