Question #9056d

1 Answer
Feb 4, 2016

I count four different trisaccharides that can be produced by the incomplete hydrolysis of amylopectin.

Explanation:

Amylopectin is a highly branched polymer of glucose. Its partial structure is

Amylopectin
(Adapted from smartkitchen.com)

I have labelled five of the glucose units as #"A, B, C, D"#, and #"E"#.

The possible trisaccharide combinations are #"ABC, DEB, EBC"#, and #"ABE"#.

α-Maltotriose (Rings #"A, B, C"#)

α-Maltotriose is formed from rings #"A, B"#, and #"C"#.

images.tutorvista.com

It consists of three glucose units joined by α-(1→4) linkages.

α-Isomaltotriose

Isomaltose is formed from rings #"D, E"#, and #"B"#.

www.sigmaaldrich.com

It consists of three glucose units joined by an α-(1→4) and an α-(1→6) linkage.

α-Panose

α-panose is formed from rings #"E, B"#, and #"C"#.

Panose

Adapted from www.chegg.com

It consists of three two glucose units joined by an α-(1→6) and an α-(1→4) linkage.

α-Isopanose

α-Isopanose is formed from rings #"A, B"#, and #"E"#.

www.chem.qmul.ac.uk

The #"A"# and #"B"# rings are joined by an α-(1-4) linkage, while the #"E"# and #"B"# rings are joined by an α-(1→6) linkage.