Question #9056d

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Answer 1 · 2016-02-04T16:27:50

I count four different trisaccharides that can be produced by the incomplete hydrolysis of amylopectin.

Amylopectin is a highly branched polymer of glucose. Its partial structure is

I have labelled five of the glucose units as #"A, B, C, D"#, and #"E"#.

The possible trisaccharide combinations are #"ABC, DEB, EBC"#, and #"ABE"#.

α-Maltotriose (Rings #"A, B, C"#)

α-Maltotriose is formed from rings #"A, B"#, and #"C"#.

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It consists of three glucose units joined by α-(1→4) linkages.

α-Isomaltotriose

Isomaltose is formed from rings #"D, E"#, and #"B"#.

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It consists of three glucose units joined by an α-(1→4) and an α-(1→6) linkage.

α-Panose

α-panose is formed from rings #"E, B"#, and #"C"#.

Panose

It consists of three two glucose units joined by an α-(1→6) and an α-(1→4) linkage.

α-Isopanose

α-Isopanose is formed from rings #"A, B"#, and #"E"#.

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The #"A"# and #"B"# rings are joined by an α-(1-4) linkage, while the #"E"# and #"B"# rings are joined by an α-(1→6) linkage.