Question #764c2

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Answer 1 · 2015-04-19T16:35:29

The volume of hydrogen is 57.4 L.

We start with the balanced equation.

#"2Al" + "6HNO"_3 → "2Al(NO"_3")"_3 + "3H"_2#

Step 1. Calculate the moles of #"Al"#.

#45.3 cancel("g Al") × "1 mol Al"/(26.98 cancel("g Al")) = "1.679 mol Al"#

Step 2. Calculate the moles of #"H"_2#.

The balanced equation tells us that 2 mol of #"Al"# give 3 mol of #"H"_2#. So,

#1.679 cancel("mol Al") × ("3 mol H"_2)/(2 cancel("mol Al")) = "2.519 mol H"_2#

Step3. To calculate the volume, we use the Ideal Gas Law:

#PV = nRT#

#V = (nRT)/P = (2.519 cancel("mol") × "0.082 06 L"·cancel("atm·K⁻¹mol⁻¹") × 300.15 cancel("K"))/(1.08 cancel("atm")) = "57.4 L"#