2C6H14+19O2---->12CO2+14H2O What mass of oxygen (O2) is required to react completely with 11.7g of C6H14?

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1 Answer
Ernest Z.
Mar 19, 2015

You will need 41.3 g of oxygen.

The balanced equation is

2C₆H₁₄ + 19O₂ → 12CO₂ + 14H₂O

Step 1. Calculate the moles of C₆H₁₄

#11.7 cancel("g C₆H₁₄") × "1 mol C₆H₁₄"/(86.17 cancel("g C₆H₁₄")) = "0.1358 mol C₆H₁₄"#

Step 2. Calculate the moles of O₂

#0.1358 cancel("mol C₆H₁₄") × "19 mol O₂"/(2 cancel("mol C₆H₁₄")) = "1.290 mol O₂"#

Step 4. Calculate the mass of O₂

#1.290 cancel("mol O₂") × "32.00 g O₂"/(1 cancel("mol O₂")) = "41.3 g O₂"#

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