What mass of carbon dioxide can 1.00 kg of lithium oxide absorb?

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Answer 1 · 2014-03-29T20:53:16

The LiOH can absorb 920 g of carbon dioxide.

The balanced equation is

#"2LiOH" + "CO"_2 → "Li"_2"CO"_3 + "H"_2"O"#

You must make the following conversions:

#"mass of LiOH" → "moles of LiOH" → "moles of CO"_2 → "mass of CO"_2#

#1.00 × 10^3 color(red)(cancel(color(black)("g LiOH"))) × "1 mol LiOH"/(23.95 color(red)(cancel(color(black)("g LiOH")))) = "41.8 mol LiOH"#

#41.8 color(red)(cancel(color(black)("mol LiOH"))) × ("1 mol CO"_2)/(2 color(red)(cancel(color(black)("mol LiOH")))) = "20.9 mol CO"_2#

#20.9 color(red)(cancel(color(black)("mol CO"_2))) × ("44.01 g CO"_2)/(1 color(red)(cancel(color(black)("mol CO"_2)))) = "920 g CO"_2#