Boundedness
Key Questions
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Answer:
Boundedness is about having finite limits. In the context of values of functions, we say that a function has an upper bound if the value does not exceed a certain upper limit. More...
Explanation:
Other terms used are "bounded above" or "bounded below".
For example, the function
f(x) = 1/(1+x^2)f(x)=11+x2 is bounded above by11 and below by00 in that:0 < f(x) <= 10<f(x)≤1 for allx in RR graph{1/(1+x^2) [-5, 5, -2.5, 2.5]}
The function
exp:x -> e^x is bounded below by0 (or you can say has0 as a lower bound), but is not bounded above.0 < e^x < oo for allx in RR graph{e^x [-5.194, 4.806, -0.74, 4.26]}
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Answer:
A continuous function defined on a closed interval has an upper (and lower) bound.
Explanation:
Probably the simplest boundedness theorem states that a continuous function defined on a closed interval has an upper (and lower) bound.
Proof by contradiction
Suppose
f(x) is defined and continuous on a closed interval[a, b] , but has no upper bound.Then:
AA n in NN, EE x_n in [a, b] : f(x_n) > n Since the sequence of
x_n 's lies in a bounded interval, it is dense at some point in the closure of the interval. Since the interval is closed, that must be at some pointc actually in the interval[a, b] .Since the sequence of
x_n 's is dense atc , there is some monotonically increasing sequencen_k in NN such thatx_(n_k) -> c ask->oo .Now
f(x) is continuous atc , so:lim_(x->c) f(x) = f(c) which is bounded.
But:
lim_(k->oo) x_(n_k) = c" " and" "lim_(k->oo) f(x_(n_k)) = oo is unbounded.
...contradiction.
So there is no such
f(x) lacking upper (or lower) bound. -
If the function is unbounded, the graph would progress to infinity, in some direction(s).
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Not all functions are bounded.
The simplest counter example would be
the identity functionf(x) = x
which is defined for all values ofx and can generate any value forf(x) A slightly less trivial counter example would be
the cubing functionf(x) = x^3