What is the slope, y-intercept and equation for the line that passes through these points: (-1, -8), (-6, -33), (-10, -53) and (-13, -68)?

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Answer 1 · 2018-08-03T12:16:29

Equation of the line in slope-intercept form is #y =5 x -3# and y intercept is #y=-3#

The slope of the line passing through

#(-1,-8) and (-6,-33)# is

#m= (y_2-y_1)/(x_2-x_1)= (-33+8)/(-6+1)=(-25)/-5=5#

Let the equation of the line in slope-intercept form be

#y=m x+c or y=5 x+c# , the point (-1,-8) will satisfy

the equation . #:. -8= 5*(-1)+c or c= -8+5= -3#

Therefore , y intercept is #y=-3#

Hence the equation of the line in slope-intercept form is

#y= 5 x-3 # . Check for points # (-10,-53) and (-13,-68)#

on the line , #y= 5 x -3 :. -53= 5 *(-10)-3 # or

# -53 = -53 and -68= 5 *(-13)-3 or -68=-68#

Therefore all for points satisfy the equation of line.

Equation of the line in slope-intercept form is #y =5 x -3# and

y intercept is #y=-3#

graph{5 x-3 [-10, 10, -5, 5]} [Ans]