What is the equation of the line with slope m= -3/7 m=−37 that passes through (17/13,14/7) (1713,147)?

1 Answer
KillerBunny
Jun 20, 2018

y = -3/7x + \frac{233}{91}y=−37x+23391

Explanation:

When you know a given point (x_0,y_0)(x0,y0) and the slope mm, the equation of a line is

y-y_0 = m(x-x_0)y−y0=m(x−x0)

In your case, (x_0,y_0) = (\frac{17}{13}, \frac{14}{7}) = (\frac{17}{13},2)(x0,y0)=(1713,147)=(1713,2) and m=-3/7m=−37.

Let's plug these values in the formula:

y-2 = -3/7(x-\frac{17}{13})y−2=−37(x−1713)

Although this already is the equation of the line, you may want to write in the slope-intercept form, for example. Expanding the right hand side, we have

y-2 = -3/7x+\frac{51}{91}y−2=−37x+5191

add 22 to both sides to get

y = -3/7x + \frac{233}{91}y=−37x+23391

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