How do you solve #10^(x-3)>=52#?

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How do you solve #10^(x-3)>=52#?

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Answer 1 · 2018-06-18T01:10:39

#x>=log52+3#

Explanation:

First, let #10^(x-3)=52# From then, we can add #>=# later on. Solving this equation, #log_10 52=x-3# or #log 52 =x-3#. # :. x=log52 +3#. Adding back the #>=#, #x>=log52+3#

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How do you solve #10^(x-3)>=52#?

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