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How do you find the derivative of #f(x)=ln (x^2+2)#?

1 Answer

May 7, 2018

#(2x)/(x^2 + 2 ) #

Explanation:

Chain rule: #d/dx f(g(x) ) = f'(g(x)) g'(x) #

#=> d/dx ln f(x) =( f'(x))/f(x) #

#=> d/dx ln(x^2 + 2) = (d/dx(x^2+2)) / (x^2 + 2) #

# therefore = (2x)/(x^2 + 2 ) #

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