How do you find the slope and intercept to graph #4x+3y-7=0#?

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Answer 1 · 2018-04-27T12:55:21

#m = 4/3#

#"y-int"# = #7/3#

#4x+3y-7=0#

rearrange into #y=mx+b#

#3y=-4x+7#

#y=(4x)/3+(7)/3#

#:.# slope is 4/3

#4x+3y-7=0#

#y=(4x)/3+(7)/3#

sub #x=0#

#y=(4(0))/3+(7)/3#
#y=0+(7)/3#
#y=(7)/3#

#:.# #(0, 7/3)#

graph{4x+3y-7=0 [-10, 10, -5, 5]}