How do you write the equation in slope intercept form given (10,-9);m=-2?

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Answer 1 · 2018-04-24T19:38:08

#y =-2x-19#

Since we are provided the slope and a point on the line we can use the equation for point slope form of the equation of a line.

#y-y_1 =m(x-x_1)#

Where #m=# slope and the point is #(x_1,y_1)#

For this situation #m=-5# and a point of #(10,-9)#

#m=-2#
#x_1=10#
#y_1=-9#

#y-y_1 =m(x-x_1)#

Plug in the values
#y-(-9) =-2(x-10)#

Simplify the signs
#y+9 =-2(x+10)#

Use distributive property to eliminate the parenthesis
#y+9 =-2x-20#

Use the additive inverse to isolate the #y# value
#y cancel(+9) cancel(-9) =-2x-10-9#

Simplify the common terms
#y =-2x-19#