How do you find the derivative of #f(x)= [(2x-5)^5]/[(x^2 +2)^2]# using the chain rule?

1 Answer
Mauricio M.
Apr 18, 2018

#= (10(2x-5)^4*(x^2+2)^2 - (2x-5)^5*4x(x^2+2))/(x^2+2)^4#

Explanation:

# f'(x) = (f'(x) * g(x) - f(x) * g'(x))/(g(x))^2 #

#f'(x) = (((5(2x-5)^4*2)(x^2+2)^2) - (2x-5)^5*(2(x^2+2)*2x))/((x^2+2)^2)^2#

#= (10(2x-5)^4*(x^2+2)^2 - (2x-5)^5*4x(x^2+2))/(x^2+2)^4#

You can reduce more, but it's bored solve this equation, just use algebraic method.

Related questions
See all questions in Chain Rule
Impact of this question
1477 views around the world
You can reuse this answer
Creative Commons License