How do you solve #4<=x+1<8#?

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Answer 1 · 2018-04-15T04:18:53

The solution is #3<=x<7#.

You can subtract #1# from all of the "sides", just like you would in a regular inequality:

#4color(white)(color(white)-1)<=x+1color(white)(color(white)-1)<8color(white)(color(white)-1)#

#4color(blue)-color(blue)1<=x+1color(blue)-color(blue)1<8color(blue)-color(blue)1#

#4color(blue)-color(blue)1<=xcolor(red)cancelcolor(black)(color(black)+1color(blue)-color(blue)1)<8color(blue)-color(blue)1#

#4color(blue)-color(blue)1<=xcolor(white)(color(white)+1-1)<8color(blue)-color(blue)1#

#3color(white)(color(white)-1)<=xcolor(white)(color(white)+1-1)<8color(blue)-color(blue)1#

#3color(white)(color(white)-1)<=xcolor(white)(color(white)+1-1)<7#

That's the solution set. Hope this helped!