How do you solve $6( x - 3) - 4( x + 1) \geq 2x - 13$ ?

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How do you solve $6( x - 3) - 4( x + 1) \geq 2x - 13$ ?

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Answer 1 · 2018-04-11T14:49:18

There is no solution

Explanation:

Expand and simplify.

$6(x-3)-4(x+1) geq 2x-13$
$6x-18 - 4x - 4 geq 2x-13$

$2x-22 geq 2x-13$

$-9 geq 0$

Now this is obviously absurd so the inequality does not hold.

There is no solution for this. If you graph $y=(6x-3)-4(x+1)$ and $y=2x-13$ you can see that the two lines are parallel and never intersect and that $y=2x-13$ is always greater.

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How do you solve $6( x - 3) - 4( x + 1) \geq 2x - 13$ ?

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How do you solve $6( x - 3) - 4( x + 1) \geq 2x - 13$ ?