What is the equation of the line with slope $m = \frac{12}{11}$ $m= 12/11$ that passes through $(- 2, 11)$ $(-2,11)$ ?

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What is the equation of the line with slope $m = \frac{12}{11}$ $m= 12/11$ that passes through $(- 2, 11)$ $(-2,11)$ ?

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Answer 1 · 2018-04-09T03:24:53

$y = \frac{12}{11} x + \frac{145}{11}$ $y=12/11x+145/11$

Explanation:

The equation of a line in slope-intercept form is $y = m x + b$ $y=mx+b$ .

We are given $x$ $x$ , $y$ $y$ , and $m$ $m$ .

So, plug these values in:
$11 = \frac{12}{11} \cdot - 2 + b$ $11=12/11*-2+b$
$11 = - \frac{24}{11} + b$ $11=-24/11+b$
$11 + \frac{24}{11} = b$ $11+24/11=b$
$\frac{121}{11} + \frac{24}{11} = b$ $121/11+24/11=b$
$\frac{145}{11} = b$ $145/11=b$
This is how I would leave it but feel free to turn it into a mixed fraction or decimal.

So, our equation is $y = (\frac{12}{11}) x + \frac{145}{11}$ $y=(12/11)x+145/11$

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What is the equation of the line with slope $m = \frac{12}{11}$ $m= 12/11$ that passes through $(- 2, 11)$ $(-2,11)$ ?

1 Answer

Explanation:

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What is the equation of the line with slope $m = \frac{12}{11}$ $m= 12/11$ that passes through $(- 2, 11)$ $(-2,11)$ ?