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How do you use the chain rule to differentiate #y=2(x^3-x)^-2#?

1 Answer

Apr 6, 2018

#-4(x^3-x)^(-3)*(3x^2-1)#

Explanation:

#(dy)/dx=d/dx(2(x^3-x)^(-2))#

#(dy)/dx=-4(x^3-x)^(-3)*d/dx(x^3-x)# (chain rule)

#(dy)/dx=-4(x^3-x)^(-3)*(3x^2-1)#

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