How do you graph using slope and intercept of #1/3x + 1/4y = 7/6#? Algebra Graphs of Linear Equations and Functions Graphs Using Slope-Intercept Form 1 Answer jk.13 Mar 28, 2018 See below Explanation: #1/4y=-1/3x+7/6# Set to slope-intercept form #y=mx+b# #y=-4/3x+28/6# multiply whole equation by 4 so that y is isolated #y=-4/3x+14/3#reduce graph{y=-4/3x+14/3 [-10, 10, -5, 5]} Answer link Related questions How do you graph #2x-3y=6# using slope intercept form? How do you graph a line using slope-intercept form? Does a graph always have a y-intercept? Where is the y-intercept of #y=2x+0.5# on a graph? How do you graph #y=-3x+5# using slope intercept form? Once you graph the y-intercept, how do you determine the second point? How do you know if you graphed the linear equation correctly? How do you graph #y=-\frac{1}{5}x-11#? How do you graph #2x + 5y = 10# using the slope and y-intercept? How do you graph #3x-5y= 10# using the slope and y intercept? See all questions in Graphs Using Slope-Intercept Form Impact of this question 1502 views around the world You can reuse this answer Creative Commons License