What are the intercepts of #-17y-x=7#? Algebra Graphs of Linear Equations and Functions Intercepts and the Cover-Up Method 1 Answer Ujjwal Mar 5, 2018 #x-"intercept"=-7# #y-"intercept"=-7/17# Explanation: #-17y-x=7# For finding #x#-intercept , put #y=0#. #=> -17(0)-x=7# #=> -x=7# #=> x=-7# We got #x#-intercept #=-7#. For finding #y#-intercept , put #x=0#. #=> -17y-(0)=7# #=> -17y=7# #=> y=-7/17# We got #y#-intercept #=-7/17#. Answer link Related questions How do you use the cover-up method to solve for the x and y intercept? What are the intercepts for horizontal and vertical line graphs? What are the intercepts for #3x-4y=-5#? How do I determine the x and y intercept for the graph #6(x-1)=2(y+3)#? How do you graph #5x+y=5# using the intercepts? What needs to be done to the equation #3(x+2)=2(y+3)# before you can use either method to find... What are the intercepts for the #y=0# and #x=0# graphs? How do you sketch a graph with x-intercept of 1 and y-intercept of -5? How do you graph #2x - 3y = 9# using x- and y- intercepts? How do you use the intercepts to graph the equation #2x-4y=8#? See all questions in Intercepts and the Cover-Up Method Impact of this question 1816 views around the world You can reuse this answer Creative Commons License