How do you graph $2x - 3y = 9$ using x- and y- intercepts?

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Answer 1 · 2018-03-19T22:54:54

See a solution process below:

First, find the y-intercept: Set $x = 0$ and solve for $y$ :

$(2 * 0) - 3y = 9$

$0 - 3y = 9$

$-3y = 9$

$(-3y)/color(red)(-3) = 9/color(red)(-3)$

$y = -3$ or $(0, -3)$

Next, find the x-intercept: Set $y = 0$ and solve for $x$ :

$2x - (3 * 0) = 9$

$2x - 0 = 9$

$2x = 9$

$(2x)/color(red)(2) = 9/color(red)(2)$

$x = 9/2$ or $(9/2, 0)$

We can next plot the two points on the coordinate plane:

graph{(x^2+(y+3)^2-0.075)((x-(9/2))^2+y^2-0.075)=0 [-20, 20, -10, 10]}

Now, we can draw a straight line through the two points to graph the line:

graph{(2x - 3y - 9)(x^2+(y+3)^2-0.075)((x-(9/2))^2+y^2-0.075)=0 [-20, 20, -10, 10]}

How do you graph 2x - 3y = 92x - 3y = 9 using x- and y- intercepts?