What are the intercepts for #3x-4y=-5#?

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Answer 1 · 2014-11-13T16:54:49

#3x-4y=-5#

To find the #x#-intercept, set #y=0#.

#3x-4(0)=-5 => 3x=-5#

by dividing by #3#,

#=> x=-5/3#

Hence, the #x#-intercept is #-5/3#.

To find the #y#-intercept, set #x=0#.

#3(0)-4y=-5 => -4y=-5#

by dividing by #-4#,

#=> y={-5}/{-4}=5/4#

Hence, the #y#-intercept is #5/4#.

I hope that this was helpful