What are the intercepts for $3x-4y=-5$ ?

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Answer 1 · 2014-11-13T16:54:49

$3x-4y=-5$

To find the $x$ -intercept, set $y=0$ .

$3x-4(0)=-5 => 3x=-5$

by dividing by $3$ ,

$=> x=-5/3$

Hence, the $x$ -intercept is $-5/3$ .

To find the $y$ -intercept, set $x=0$ .

$3(0)-4y=-5 => -4y=-5$

by dividing by $-4$ ,

$=> y={-5}/{-4}=5/4$

Hence, the $y$ -intercept is $5/4$ .

I hope that this was helpful

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