What is the equation of the line with slope # m= -3/17 # that passes through # (11,1) #?

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Answer 1 · 2018-03-02T00:27:21

#3x+17y=50#

From the given
slope #m=-3/17# and #(11, 1)#

Use Point-Slope Form

#y-y_1=m*(x-x_1)#

#y-1=(-3/17)(x-11)#
Multiply both sides of the equation by #17#
#17(y-1)=17(-3/17)(x-11)#
#17y-17=-3(x-11)#
#17y-17=-3x+33#

The required equation is

#3x+17y=50#

God bless....I hope the explanation is useful.