How do you write the standard form of a line given slope of 43− and passes through the point (4, 5)?

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Answer 1 · 2017-12-04T14:21:19

#y=43x-167#

I'm assuming you meant that the gradient was #43#:

The standard equation of a straight line with gradient #m# and intercepting the y axis at #c# is:

#y=mx+c#

Since the line passes through the point #(4,3)#, we can form the following equation and solve for #c#:

#5 = 43(4) + c#
#c = -167#

Hence,
#y=43x - 167#