How do you condense $log 2 ln 8 + 5 ln z$ $log 2 ln 8 +5 ln z$ ?

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Answer 1 · 2017-07-20T06:50:46

$ln (\sqrt[ln 10]{8^{ln 2}} \cdot z^{5})$ $ln(root(ln10)(8^ln2)*z^5)$

We know that $log x = \frac{ln x}{ln 10}$ $logx=lnx/ln10$ so let's use this.

$log 2 ln 8 + 5 ln z = \frac{ln 2}{ln 10} \cdot ln 8 + {ln z}^{5} =$ $log2ln8+5lnz=ln2/ln10*ln8+lnz^5=$

${ln 8}^{\frac{ln 2}{ln 10}} + {ln z}^{5} = ln (\sqrt[ln 10]{8^{ln 2}} \cdot z^{5})$ $ln8^(ln2/ln10)+lnz^5=ln(root(ln10)(8^ln2)*z^5)$

How do you condense log2ln8+5lnzlog 2 ln 8 +5 ln z?