How do you solve 2(x-3)^2=8?

2 Answers
Martha W. · EZ as pi
Jul 11, 2017

x=5 or x=1

See below

Explanation:

2(x−3)^2=8

Divide both sides by 2: (x-3)^2=4

Take the square root of each side:

(x-3)=+-2

x-3=+2" "rarrx=5
or
x-3=-2" "rarrx=1

x=5 or x=1

Amanuel S.
Jul 11, 2017

The answer is x= 5 and 1

Explanation:

First you start by evualting the 2(x-3)^2 part of the equation.
2(x-3)^2=8
2(x^2-6x+9)=8
2x^2-12x+18=8
Then you move over the constant on the right side to the left .
2x^2-12x+18-8=0
2x^2-12x+10=0
Then divide the whole equation by 2.
(2x^2-12x+10)/2=0/2
x^2-6x+5=0
Then factor the equation normally.
(x-5)(x-1)=0

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