Question #ba724 Algebra Graphs of Linear Equations and Functions Slope-Intercept Form 1 Answer kingsito · EZ as pi Apr 10, 2017 graph{y=-8x-1 [-10, 10, -5, 5]} slope of #-8/1# y-int# = (0,-1#) Explanation: #-1# is the intercept on the y axis, which the line passes through. #-8# is the slope of the line. In this case, since #m =-8=-8/1#, from #(0,-1)# you must move down #8# units and then go right #1# unit to give a negative slope. The the rule of slope is #"rise"/" run"# or #"change in y"/"change in x"#. Answer link Related questions What is Slope-Intercept Form? How do you find the "m" and "b" of any linear equation? How do you determine the slope and y intercept when given a graph? Why is slope "rise over run"? How do you find the slope and y intercept of #2x+5=y#? What is the slope and y intercept of #y=x#? What is the slope and y intercept of #y=3.75#? How do you write #7+\frac{3}{5} x=y# in slope intercept form? How do you write #-5x+12=20# in slope intercept form? How do you write an equation in standard form for a line that goes through (5, –2) and (–5, 4)? See all questions in Slope-Intercept Form Impact of this question 1956 views around the world You can reuse this answer Creative Commons License