How do you solve $x + \frac{2}{x} = 3$ $x+2/x=3$ ?

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How do you solve $x + \frac{2}{x} = 3$ $x+2/x=3$ ?

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Answer 1 · 2017-02-08T21:41:00

$x = 1$ $x=1$ or $x = 2$ $x=2$

Explanation:

$x + \frac{2}{x} = 3$ $x+ 2/x = 3$
$\frac{2}{x} = 3 - x$ $2/x = 3-x$
$2 = x (3 - x)$ $2 = x(3-x)$
$2 = 3 x - x^{2}$ $2= 3x-x^2$
$x^{2} - 3 x + 2 = 0$ $x^2-3x+2=0$
$(x - 1) (x - 2) = 0$ $(x-1)(x-2)=0$

$x - 1 = 0$ $x-1 = 0$ or $x - 2 = 0$ $x-2 = 0$
$x = 1$ $x=1$ or $x = 2$ $x=2$

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How do you solve $x + \frac{2}{x} = 3$ $x+2/x=3$ ?

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