How do you solve $c^{2} + 10 c + 9 = 0$ $c^2+10c+9=0$ ?

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Answer 1 · 2017-02-08T21:26:17

$c = - 1$ $c = -1$ or $c = - 9$ $c = -9$

$c^{2} + 10 c + 9 = 0$ $c^2 + 10c + 9 = 0$
$(c + 1) (c + 9) = 0$ $(c + 1)(c+9) = 0$

$c + 1 = 0$ $c+1=0$ or $c + 9 = 0$ $c+9 = 0$
$c = - 1$ $c=-1$ or $c = - 9$ $c=-9$

How do you solve c2+10c+9=0c^2+10c+9=0?