How do you solve $20 p^{2} - 15 p = 0$ $20p^2-15p=0$ ?

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Answer 1 · 2017-02-08T20:59:33

$p = 0$ $p = 0$ or $p = \frac{3}{4}$ $p = 3/4$

the equation:
$20 p^{2} - 15 p = 0$ $20p^2 - 15p = 0$

if you put that in brackets:
$5 p (4 p - 3) = 0$ $5p(4p-3) = 0$

now you can calculate that:
$5 p = 0$ $5p = 0$ or $4 p - 3 = 0$ $4p - 3 = 0$
$p = 0$ $p = 0$ or $4 p = 3 \to p = \frac{3}{4}$ $4p = 3 -> p = 3/4$

How do you solve 20p2−15p=020p^2-15p=0?