Question #b2dc7

1 Answer
Jan 23, 2017

d/dxln(ln(1-x))=-1/((1-x)ln(1-x))ddxln(ln(1x))=1(1x)ln(1x)

Explanation:

Using the chain rule, along with the derivative d/dxln(x) = 1/xddxln(x)=1x:

d/dxln(ln(1-x)) = 1/ln(1-x)(d/dxln(1-x))ddxln(ln(1x))=1ln(1x)(ddxln(1x))

=1/ln(1-x)(1/(1-x))(d/dx(1-x))=1ln(1x)(11x)(ddx(1x))

=1/((1-x)ln(1-x))(-1)=1(1x)ln(1x)(1)

=-1/((1-x)ln(1-x))=1(1x)ln(1x)