How do you write $4y-8x+12=0$ in slope intercept form?

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Answer 1 · 2016-11-26T17:19:15

$y= 2x-3$

$y = mx +c$ is known as slope-intercept form

Rewrite the equation to get it in the form $y =.....$

$4y = 8x - 12" "$ (leave just the y on one side)

$y = 2x - 3" "$ (divide all by 4)

How do you write 4y-8x+12=04y-8x+12=0 in slope intercept form?