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How do you find the derivative of #f(x)=sqrt(169-x^2)#?

1 Answer

Nov 25, 2016

Using chain rule, which states that #dy/dx=(dy)/(du)(du)/dx#.

Explanation:

Here, we'll rename #y=sqrt(u)# and #u=169-x^2#

Thus:

#(dy)/(dx)=1/(2(u)^(1/2))*(-2x)=-1/sqrt((169-x^2))#

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