How many solutions does #x^2-6=0# have? Algebra Quadratic Equations and Functions Solutions Using the Discriminant 1 Answer S.S · EZ as pi Nov 13, 2016 2 Explanation: #x^2 - 6 = 0# #x^2 = 6# #x = sqrt(6)# or #x = -sqrt(6)# This is because #(-sqrt(6)) xx (-sqrt(6))# is also #6# because two negatives multiplied together make a positive. Answer link Related questions How do you find the number of solutions using the discriminant? What is the Discriminant? How does the discriminant affect the graph? Why is the discriminant useful? How do you determine the number of real solutions to #-3x^2+4x+1=0#? Can you find a discriminant for a linear equation? What is the discriminant of #2x^2-4x+5=0#? What type of solutions and how many solutions does the equation #41x^2-31x-52=0# have? How do you determine if a solution to a quadratic equation is rational or irrational by using... Is the solution to #x^2=5x# rational or irrational? See all questions in Solutions Using the Discriminant Impact of this question 2482 views around the world You can reuse this answer Creative Commons License