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How do you condense #ln(1+x^9)+1/2(ln(x)-ln(sin(x) #?

1 Answer

Sep 14, 2016

#ln(1+x^9)+1/2lnx-ln(sinx)=(1+x^9)/(2sinx)#

Explanation:

Use the following 2 laws of logs :

#logAB=logA+logB#

#log(A/B)=logA-logB#

to get :

#ln(1+x^9)+1/2lnx-ln(sinx)=(1/2(1+x^9))/sinx#

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