How do you use the chain rule to differentiate #y=sin^3(2x+1)#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Euan S. Aug 8, 2016 #(dy)/(dx) = 6sin^2(2x+1)cos(2x+1)# Explanation: #u(x) = 2x+1 # so # (du)/(dx) = 2# #y = sin^3(u) implies (dy)/(du) = 3sin^2(u)cos(u)# #(dy)/(dx) = (dy)/(du)(du)/(dx)# #(dy)/(dx) = 6sin^2(2x+1)cos(2x+1)# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 9440 views around the world You can reuse this answer Creative Commons License